16x^2-24x-63=0

Solution for 16x^2-24x-63=0 equation:

16x^2-24x-63=0

a = 16; b = -24; c = -63;
Δ = b2-4ac
Δ = -242-4·16·(-63)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-48\sqrt{2}}{2*16}=\frac{24-48\sqrt{2}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+48\sqrt{2}}{2*16}=\frac{24+48\sqrt{2}}{32}
$